3y^2-1/2(y+1)

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Solution for 3y^2-1/2(y+1) equation: 


y in (-oo:+oo)

3*y^2-((1/2)*(y+1)) = 0

(-1/2)*(y+1)+3*y^2 = 0

3*y^2-1/2*(y+1) = 0

3*y^2-1/2*(y+1) = 0

3*y^2-1/2*y-1/2 = 0

3*y^2-1/2*y-1/2 = 0

3*y^2-1/2*y-1/2 = 0

DELTA = (-1/2)^2-(-1/2*3*4)

DELTA = 25/4

DELTA > 0

y = ((25/4)^(1/2)+1/2)/(2*3) or y = (1/2-(25/4)^(1/2))/(2*3)

y = 1/2 or y = -1/3

(y+1/3)*(y-1/2) = 0

(y+1/3)*(y-1/2) = 0

( y+1/3 )

y+1/3 = 0 // - 1/3

y = -1/3

( y-1/2 )

y-1/2 = 0 // + 1/2

y = 1/2

y in { -1/3, 1/2 }

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